Elisa_Plaza

Week 3

1) i. To find A you need to do algebra between the two equations given. To find B you subract the values you got for A from the first equation given.

ii.To find the magnitude of A and B you do the equation sqrt(Ax^2+Ay^2) and sqrt(Bx^2+By^2) to find B. You input the i^ values for x and the j^ values for y.

iii. To find the angles use the tangent equation and input the values needed and solve for theta.

Week 4

Vo=10.5 m/s g=9.8 m/s^2 Distance from building that the ball lands=15.3 m angle falls =54 degrees

1. you need to do tan(54)=15.3/h (where h is the height of the building). this will help you find the height. you can do this because the building makes a right angle with the ground.

**Professor's Note : Correct steps on i and ii. Check my page for part iii**

week 5

a) first you have to find time by using delta y=1/2*9.8*t^2 --> 5.4= 1/2*9.8*t^2. when you have time you put that into delta x equation with the acceleration as 0 m/s^2 and delta x as 8. this will find the initial velocity

b) to find the delta x at 2.7 m high as the delta y you need to refind time with the delta y equation and then input that value into the delta x equation using acceleration as 0 and the initial velocity as the one you found in the previous question

Week 9

A) Find work by using the equation W=F*D*cos(angle) but before you do that you need to find F by using F=m*a. The final answer for work will be in Joules. Tcos(0)+mgcos(180)=ma T=mg+ma W=(mg+m(g/4)*d

B) Find work done by gravitational force by W=F*D*cos(angle), but first you need to Find F again by F=mg W=mgdcos(0) W=mgd


 * You have to do part D) first to get the speed to use in part C)

C) Find the kinetic energy by using KE=(1/2)mv^2, use the V (speed) that you found in part d KE=(1/2)m(sqrt(2(g/4)d)

D) Find speed of block by the equation V^2=Vo^2+2a(delta d) but know that Vo=0, so the final equation will be V=sqrt(2(g/4)d)

visited and NO new work posted, re-visit later-- professor