Christopher+Enderby

__Week Four__

1. First we must find the total time the rock is in the air. We can do this by finding the velocity of the rock along the x-axis, found by the equation Vx=Vcos(theta), and entering that value into the equation (delta)x=Vxt+.5at^2 knowing that a=0

2. With t found, we simply need to find the initial velocity along the y-axis, found by Vy=Vsin(theta), and we will have all the necessary variables to solve for the height of the building. Plugging the variables into the equation (delta)x=Vyt+.5at^2, we will find be able to find (delta)x, which is equivalent to the height of the building.

__Week Five__

a. 1. Using the known values, we first find the time it takes for the fish to hit the water. Since the initial velocity of the fish in the y-direction is zero, this is just a free fall equation, so we use (delta)x=.5at^2.

2. With the time discovered, we are now able to figure out the initial velocity of the fish along the x-axis. Again we use the equation (delta)x=Vit+.5at^2, yet since there is no acceleration in the x-axis, the equation is (delta)x=Vit. With this we can find the initial speed of the fish, which is equal to the speed of the pelican.

b. 1. Again we start with finding the time it takes for the fish to hit the water. We use the same equation (delta)x=.5at^2, yet this time changing the (delta)x from -5.4, to -2.7m.

2. With the time figured out, we again plug the known values into the equation (delta)x=Vit to figure out the distance traveled in the x-axis, only this time we know the initial speed, rather than the distance. Using this, we are able to figure out the horizontal distance the fish falls before hitting the water.

__Week Seven__

1. a. Since the car is moving at a constant speed, the balance will read 65N b. You first have to find the mass hanging from the scale by using F=ma with gravity being the acceleration, and 65N being the force. With the mass being found, multiply it by the new acceleration to find what the balance reads.